(48y^2+8y+7)/(12y-1)

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Solution for (48y^2+8y+7)/(12y-1) equation: 


D( y )

12*y-1 = 0

12*y-1 = 0

12*y-1 = 0

12*y-1 = 0 // + 1

12*y = 1 // : 12

y = 1/12

y in (-oo:1/12) U (1/12:+oo)

(48*y^2+8*y+7)/(12*y-1) = 0

48*y^2+8*y+7 = 0

48*y^2+8*y+7 = 0

DELTA = 8^2-(4*7*48)

DELTA = -1280

DELTA < 0

1 = 0

1/(12*y-1) = 0

y belongs to the empty set

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